מתקנים ביתיים ותאורה

✦ בנוי על ידי פהד גאנם ✦

I = PU   |   nx = n − 2   |   U = 230 V   |   f = 50 Hz
1.0×
0
0
0
0

n = 3   |   nx = n − 2 = 1
S1 X S2 L
1=1
1=2
1×1
1×2
2=1
2=2
2×1
2×2
I = PU = 8 W230 V = 0.03 A

I = PU   |   ΔU = I · R   |   R = ρ · 2LA   |   Uend = U − ΔU   |   U = 230 V   |   ρCu = 0.0175 Ω·mm²/m
16 A
40 A
0
0
0
0

I1 = P1U = 2000 W230 V = 8.70 A
I2 = P2U = 900 W230 V = 3.91 A
I = I1 + I2 = 8.70 A + 3.91 A = 12.61 A
R = ρ · 2LA = 0.0175 · 2 · 202.5 = 0.28 Ω
ΔU = I · R = 12.61 A · 0.28 Ω = 3.53 V Uend = 230 V − 3.53 V = 226.47 V ΔUU = 3.53 V230 V = 1.54 %

Φ = η · P   |   P = Φη   |   E = ΦA   |   [η] = lmW    [E] = lux
800 lm
2400 lm
20 m²
0
0
0

P = Φη = 800 lm13 lm/W = 61.5 W
P = Φη = 800 lm120 lm/W = 6.7 W
ΔP = 61.5 W − 6.7 W = 54.8 W PincPLED = ηLEDηinc = 120 lm/W13 lm/W = 9.2
E = ΦA = 2400 lm20 m² = 120 lux

E = P · t   |   E [kWh] = P [W] · t [h]1000   |   ΔE = (P1 − P2) · t   |   ΔEE1 · 100 %   |   Φ = η · P
10
5.0 h
0.50 ₪
0
0
0
0
0
0

t = 5 h · 365 = 1825 h
P1 = 10 · 60 W = 600 W P1 = 600 W1000 = 0.6 kW E1 = P1 · t = 0.6 · 1825 = 1095 kWh
P2 = 10 · 8 W = 80 W P2 = 80 W1000 = 0.08 kW E2 = P2 · t = 0.08 · 1825 = 146 kWh
ΔE = E1 − E2 = 1095 − 146 = 949 kWh ΔEE1 · 100 = 949 kWh1095 kWh · 100 = 86.7 %
Cost = ΔE · T = 949 kWh · T

I = PU  |  ΔU = I·R  |  R = 2ρLA  |  Φ = η·P  |  E = ΦA  |  U = 230 V
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