פתרון בגרות · מכניקה

✦ בנוי על ידי פהד גאנם ✦

t (s)   |  0  |  0.1  |  0.2  |  0.3  |  0.4  |  0.5
v₁ (m/s) |  1.0  |  0.5  |  0  |  −0.5  |  −1.0  |  −1.5
v₂ (m/s) |  −0.5  |  −1.0  |  −1.5  |  −2.0  |  −2.5  |  −3.0
a = ΔvΔt = −5 m/s²  ;  a = g·sinα  ;  sinα = 0.5  ;  α = 30°
0.000 s
0.000 s
+1.000 m/s
0.125 m
0.063 m
0.000 m
0.000 s
−0.500 m/s
1.271 m
0.635 m
0.000 m
−5.000 m/s²
30°
1.000 m/s
0.500 m/s

(0 , 1.0)   (0.1 , 0.5)   (0.2 , 0)   (0.3 , −0.5)   (0.4 , −1.0)   (0.5 , −1.5) a = ΔvΔt = −1.5 − 1.00.5 − 0 = −2.50.5 = −5 m/s²
(0 , −0.5)   (0.1 , −1.0)   (0.2 , −1.5)   (0.3 , −2.0)   (0.4 , −2.5)   (0.5 , −3.0) a = −3.0 − (−0.5)0.5 − 0 = −2.50.5 = −5 m/s²
v₁ = 1.0 m/s  ;  v₂ = 0.5 m/s
a = g·sinα  ;  sinα = 510 = 0.5  ;  α = 30°

ΣF = m·g·sinα  ;  a = g·sinα = 5 m/s²
a = −5 m/s²  ;  a  =  −g·sinα
v₁(0) = +1.0 m/s  ;  v₂(0) = −0.5 m/s

v(t) = v₁ + a·t = 0 ttop = v₁|a| = 1.05 = 0.2 s
Δt = 0.5 − 0.2 = 0.3 s
d = 12·|a|·Δt² = 12 · 5 · (0.3)² = 12 · 5 · 0.09 = 0.225 m
vK = −1.5 m/s  ;  vK² = 0 + 2·|a|·d d = vK²2·|a| = (1.5)²2 · 5 = 2.2510 = 0.225 m
12·m·vK² = m·g·d·sinα d = vK²2·g·sinα = 2.252 · 10 · 0.5 = 0.225 m
S = 12 · 0.3 · 1.5 = 0.225 m

0 = v₁² − 2·|a|·dup dup = v₁²2·|a| = (1.0)²2 · 5 = 110 = 0.1 m dup = v₁·ttop12·|a|·ttop² = 0.2 − 0.1 = 0.1 m
AK = 0.225 − 0.100 = 0.125 m
Δx = v₁·t + 12·a·t² = (1.0)(0.5) + 12(−5)(0.25) = 0.5 − 0.625 = −0.125 m
S₊ = 12 · 0.2 · 1.0 = +0.100  ;  S₋ = −12 · 0.3 · 1.5 = −0.225 Δx = 0.100 − 0.225 = −0.125 m

v₀ = −0.5 m/s  ;  a = −5 m/s²  ;  t = 0.62 s
Δx = v₀·t + 12·a·t² = (−0.5)(0.62) + 12(−5)(0.3844) Δx = −0.31 − 0.961 = −1.271 m  ;  BK = 1.271 m
AB = BK − AK = 1.271 − 0.125 = 1.146 m ≈ 1.15 m
vK = v₀ + a·t = −0.5 − 5(0.62) = −3.6 m/s BK = vK² − v₀²2·|a| = 12.96 − 0.2510 = 12.7110 = 1.271 m
12vK² − 12v₀² = g·sinα·BK 6.48 − 0.125 = 5 · BK  ;  BK = 6.3555 = 1.271 m
2.5t² + 0.5t − 1.146 = 0  ;  t = 0.5844 s v = 0.5 + 5(0.5844) = 3.422 m/s  ;  Δt = 0.62 − 0.5844 = 0.0356 s d = 3.422(0.0356) + 2.5(0.0356)² = 0.1218 + 0.0032 = 0.125 m

|aup| = g·sinα + μ·g·cosα  ;  |aup|  גדול מ  5 m/s²
|adown| = g·sinα − μ·g·cosα  ;  |adown|  קטן מ  5 m/s²
μ = 5 − 1.87510 · cos30° = 3.1258.66 = 0.361 aup = −(5 + 8.66 · 0.361) = −8.125 m/s² tstop = 1.08.125 = 0.123 s
μ = 0.361  קטן מ  tan30° = 0.577

t (s)   |   0 – 0.3  |  0.3 – 0.8  |  0.8 – 1.2
T (N)   |   10       |  12        |  10
mA = 3 kg  ;  g = 10 m/s²  ;  TA = TB = T

0.00 s
0.00 s
10.00 N
40.00 N
0.00 m/s²
0.00 m/s
0.000 m
10.00 N
0.00 N

mA·g = 3 · 10 = 30 N
mB·g = 1 · 10 = 10 N

F₁ − T − mA·g = mA·a T − mB·g = mB·a
F₁ − mA·g − mB·g = (mA + mB)·a a = F₁ − (mA + mB)·gmA + mB = F₁mA + mB − g
T = mB·(g + a) = mB·F₁mA + mB

0 < t < 0.3 s  ;  a = 0  ;  T = 10 N
T − mB·g = mB · 0  ⟹  T = mB·g mB = Tg = 1010 = 1 kg
F₁ = T + mA·g = 10 + 30 = 40 N F₁ = (mA + mB)·g  ;  40 = (3 + mB) · 10  ⟹  mB = 1 kg
TF₁ = mBmA + mB = 1040 = 0.25  ⟹  mB = 0.25 · 4 = 1 kg

a = T − mB·gmB  ;  F₁ = (mA + mB)·(g + a) mA + mB = 3 + 1 = 4 kg
T = 10 N  ;  a = 10 − 1 · 101 = 0 m/s² F₁ = 4 · (10 + 0) = 40 N
T = 12 N  ;  a = 12 − 1 · 101 = 2 m/s² F₁ = 4 · (10 + 2) = 4 · 12 = 48 N
T = 10 N  ;  a = 10 − 1 · 101 = 0 m/s² F₁ = 4 · (10 + 0) = 40 N
F₁ = T + mA·g + mA·a 10 + 30 + 3 · 0 = 40 N  ;  12 + 30 + 3 · 2 = 48 N  ;  10 + 30 + 0 = 40 N
F₁ = 4 · T  ;  4 · 10 = 40  ;  4 · 12 = 48  ;  4 · 10 = 40 N

ΣF = 12 − 10 = 2 N  ;  a = 21 = 2 m/s²
Δt = 0.8 − 0.3 = 0.5 s v = v₀ + a·Δt = 0 + 2 · 0.5 = 1 m/s Δy = 12 · a · Δt² = 12 · 2 · 0.5² = 0.25 m
ΣF = 10 − 10 = 0  ;  a = 0 m/s² Δy = v·Δt = 1 · (1.2 − 0.8) = 0.4 m Δytotal = 0 + 0.25 + 0.4 = 0.65 m
ΣF = (mA + mB)·a = 4 · 2 = 8 N  ;  W = 8 · 0.25 = 2 J ΔEk = 12 · 4 · 1² − 0 = 2 J WF₁ = 40 · 0.4 = 16 J  ;  Wg = −40 · 0.4 = −16 J  ;  W = 0

F₁ − (mA + mB)·g = (mA + mB)·a₁ F₁ = (mA + mB)·(g + a₁)
F₁ − F₂ − mA·g = mA·a₁  ⟹  F₂ = F₁ − mA·(g + a₁)
F₂ = (mA + mB)·(g + a₁) − mA·(g + a₁) = mB·(g + a₁) a₁ > 0  ⟹  g + a₁ > g  ⟹  F₂ = mB·(g + a₁) > mB·g
F₂ = T  ;  T − mB·g = mB·a₁  ⟹  T = mB·(g + a₁)
F₁ = 4 · (10 + 2) = 48 N  ;  T = 1 · (10 + 2) = 12 N F₂ = 48 − 3 · 12 = 48 − 36 = 12 N  ;  mB·g = 10 N F₂mB·g = 1210 = 1.2 > 1

h = 6 m  ;  v₀ = 3 m/s  ;  Δt = 0.5 s  ;  g = 10 m/s²
x = v₀·t   ;   y = h − 12·g·t²   ;   vy = g·t
v = vx² + vy²   ;   v² = v₀² + 2·g·h
6.00 m
3.00 m/s
0.50 s
3
×0.25
0.000 s
6.00 m
3.00 m/s
0.00 m/s
3.00 m/s
0.00 °
1.0954 s
10.9545 m/s
11.3578 m/s
74.68 °
3.2863 m
1.50 m
30.0 °
0.9557 s
2.5981 m/s
11.0567 m/s
11.3578 m/s

v0x = v₀ = 3 m/s  ;  v0y = 0  ;  ay = g = 10 m/s²
h = v0y·t + 12·g·t² = 12·g·t² t = 2·hg = 2 · 610 = 1.2 = 1.0954 s
vy² = v0y² + 2·g·h = 0 + 2 · 10 · 6 = 120 vy = 120 = 10.9545 m/s h = vy2·t  ;  t = 2·hvy = 1210.9545 = 1.0954 s

vx = v₀ = 3 m/s
vy = g·t = 10 · 1.0954 = 10.9545 m/s
v = vx² + vy² = 3² + 10.9545² = 9 + 120 = 129 v = 11.358 m/s ≈ 11.4 m/s
tan θ = vyvx = 10.95453 = 3.6515 θ = 74.68° ≈ 74.7°
12·m·v₀² + m·g·h = 12·m·v² v² = v₀² + 2·g·h = 9 + 120 = 129  ;  v = 129 = 11.358 m/s

t = 2·hg = 1.0954 s
x = vx·t = 3 · 1.0954 = 3.2863 m ≈ 3.29 m
Δx = (x2 + v·t) − (x1 + v·t) = x2 − x1 = v₀·Δt Δx = 3 · 0.5 = 1.5 m
x1 = 0 + 3 · 1.0954 = 3.2863 m x2 = 1.5 + 3 · 1.0954 = 4.7863 m x2 − x1 = 4.7863 − 3.2863 = 1.5 m

d = 12·g·t² d3 = 0  ;  d2 = 12 · 10 · 0.5² = 1.25 m  ;  d1 = 12 · 10 · 1.0² = 5.00 m 1.25 − 0 = 1.25 m  ;  5.00 − 1.25 = 3.75 m  ;  1.25 : 3.75 = 1 : 3
y3 = 6 m  ;  y2 = 6 − 1.25 = 4.75 m  ;  y1 = 6 − 5.00 = 1 m

12·m·v₀² + m·g·h = 12·m·v² v² = v₀² + 2·g·h
v = 3² + 2 · 10 · 6 = 9 + 120 = 129 = 11.358 m/s ≈ 11.4 m/s
vx = v₀·cos α  ;  vy² = (v₀·sin α)² + 2·g·h v² = v₀²·cos²α + v₀²·sin²α + 2·g·h = v₀²·(cos²α + sin²α) + 2·g·h = v₀² + 2·g·h v² = 9 + 120 = 129  ;  v = 11.358 m/s


h (m)   |  0.6  |  0.8  |  1.0  |  1.2  |  1.4
NC (N) |  0.20 |  0.55 |  0.75 |  0.95 |  1.20
NC,min = 0.6 N  ;  g = 10 m/s²
1.000 m
1.000 m
1.000 m
0.00 m/s
4.47 m/s
3.71 m/s
0.73 N
0.0940 J
0.313 m

mg  ;  N  ;  N + mg = ΣFradial
NC = N

m·g·h = m·g·(2R) + ½·m·vC2 vC2 = 2·g·(h − 2R)
N + m·g = m·vC2R N = m·vC2R − m·g = m·2·g·(h − 2R)R − m·g
N = 2·m·gR·h − 4·m·g − m·g NC = 2·m·gR·h − 5·m·g
aslope = 2·m·gR  ;  b = −5·m·g
m·g = m·vC2R  ;  vC2 = g·R 2·g·(h − 2R) = g·R  ;  h = 2.5·R NC = 2·m·gR·(2.5·R) − 5·m·g = 5·m·g − 5·m·g = 0

(0.6 , 0.20)   (0.8 , 0.55)   (1.0 , 0.75)   (1.2 , 0.95)   (1.4 , 1.20)
aslope = ΔNCΔh = 1.21 − 0.251.4 − 0.6 = 0.960.8 = 1.20 N/m
b = 0.25 − 1.20 · 0.6 = 0.25 − 0.72 = −0.47 N NC = 1.20 · h − 0.47
h̄ = 5.05 = 1.000 m  ;  N̄ = 3.655 = 0.730 N aslope = Σ(h − h̄)(N − N̄)Σ(h − h̄)2 = 0.4800.400 = 1.2000 N/m b = N̄ − aslope·h̄ = 0.73 − 1.2 · 1.0 = −0.4700 N

NC = 2·m·gR·h − 5·m·g     NC = 1.20 · h − 0.47
5·m·g = 0.47 N m·g = 0.475 = 0.094 N m = 0.09410 = 0.0094 kg = 9.4 g
2·m·gR = 1.20 N/m R = 2 · 0.0941.20 = 0.1881.20 = 0.1567 m ≈ 0.157 m 2R = 0.3133 m
5·m·g2·m·gR = 2.5·R = 0.471.20 = 0.3917 m R = 0.39172.5 = 0.1567 m
vC2 = 2·g·(h − 2R) = 20 · (1.0 − 0.3133) = 13.733 m²/s² NC = m·vC2R − m·g = 0.0094 · 13.7330.1567 − 0.094 = 0.824 − 0.094 = 0.73 N

0.60 = 1.20 · hmin − 0.47 1.20 · hmin = 1.07 hmin = 1.071.20 = 0.8917 m ≈ 0.89 m
hmin = R·(NC,min + 5·m·g)2·m·g = 0.1567 · (0.60 + 0.47)0.188 = 0.8917 m
vC2 = 2·g·(hmin − 2R) = 20 · (0.8917 − 0.3133) = 11.567 m²/s² vC = 11.567 = 3.40 m/s NC = m·vC2R − m·g = 0.0094 · 11.5670.1567 − 0.094 = 0.694 − 0.094 = 0.600 N

0 = 1.20 · h1 − 0.47  ;  h1 = 0.471.20 = 0.3917 m ≈ 0.39 m
m·g = m·vC2R  ;  vC2 = g·R
vC = g·R = 10 · 0.1567 = 1.5667 = 1.25 m/s
vC2 = 2·g·(h1 − 2R) = 20 · (0.3917 − 0.3133) = 20 · 0.07833 = 1.5667 m²/s² vC = 1.5667 = 1.25 m/s

g = 10 m/s²  ;  mA = 0.4 kg  ;  mB = 1.2 kg
h = 0.6 m  ;  xA = 1.5 m  ;  vB = 4 m/s
m·g·h = 12·m·v²  ;  Wf = −μ·m·g·x  ;  J = Δp
0.600 m
0.400
30°
0.400 kg
0.800 m
1.000
0.600 m
30°
60°
3.464 m/s
4.000 m/s²
1.500 m
0.866 s
0.000 m/s
0.000 m
0.000 s
0.000 J
2.400 J
0.000 J
4.000 m/s
2.000 m/s
6.000 m/s
−2.400 N·s
2.400 N·s
9.600 J
9.600 J
0.000 m/s
3.464 m/s
5.000 m/s²
8.660 m/s²
0.693 s
0.400 s
1.386 N·s
1.386 N·s
0.000 N·s
0.000 N·s

WN = N · d · cos90° = 0 ΔEmech = Wnon-cons = 0  ;  Ek + Ep = const
Wf = −fk · x = −μ·m·g·x
ΔpΔt = ΣF ΣF = m·g·sinθ ≠ 0 ΣF = −μ·m·g ≠ 0

mA·g·h = 12·mA·v² v = 2·g·h = 2 · 10 · 0.6 = 12 = 3.46 m/s
12·mA·v² = μ·mA·g·xA μ = 2 · g · xA = 122 · 10 · 1.5 = 1230 = 0.4
mA·g·h = μ·mA·g·xA μ = hxA = 0.61.5 = 0.4
a = −μ·g = −0.4 · 10 = −4 m/s² vf² = v² + 2·a·xA = 12 + 2·(−4)·1.5 = 12 − 12 = 0 t = vμ·g = 3.46414 = 0.866 s x = v · t2 = 3.4641 · 0.8662 = 1.5 m

mB·g·h = μ·mB·g·xB xB = hμ = 0.60.4 = 1.5 m
Ep = m·g·h  ;  fk = μ·m·g  ;  x = hμ
v = 2·g·h = 12 m/s  ;  a = μ·g = 4 m/s² x = 2 · a = 128 = 1.5 m

mB·vB = mA·v′A + mB·v′B  ;  1.2 · 4 = 0.4·v′A + 1.2·v′B 12·mB·vB² = 12·mA·v′A² + 12·mB·v′B²
v′B = mB − mAmA + mB·vB = 1.2 − 0.41.6·4 = 2 m/s v′A = 2·mBmA + mB·vB = 2.41.6·4 = 6 m/s
JB = ΔpB = mB·v′B − mB·vB = 1.2·2 − 1.2·4 = 2.4 − 4.8 = −2.4 N·s
JA = mA·v′A − 0 = 0.4 · 6 = 2.4 N·s JA + JB = 2.4 − 2.4 = 0
Ek = 12·1.2·4² = 9.6 J  ;  12·1.2·2² + 12·0.4·6² = 2.4 + 7.2 = 9.6 J vB − vA = 4 − 0 = 4 m/s  ;  v′A − v′B = 6 − 2 = 4 m/s
xA = 2 · 4 = 4.5 m  ;  xB = 2 · 4 = 0.5 m HB = vB²2 · g = 1620 = 0.8 m

J = Δp = mA·v − mA·0 = mA·v
mA·g·H = 12·mA·v²  ;  v = 2·g·H J1 = mA·2·g·H = J2
t = vg · sinθ  ;  Jgrav = m·g·t
v = 2 · 10 · 0.6 = 3.4641 m/s a1 = 10·sin30° = 5 m/s²  ;  t1 = 3.46415 = 0.6928 s  ;  Jgrav = 2.7713 N·s a2 = 10·sin60° = 8.6603 m/s²  ;  t2 = 3.46418.6603 = 0.4 s  ;  Jgrav = 1.6 N·s J1 = 0.4 · 3.4641 = 1.3856 N·s  ;  J2 = 0.4 · 3.4641 = 1.3856 N·s

r (109 m)  |  b = 1.73  |  c = 2.36  |  d = ?
T (86400 s)  |  b = 1.51  |  c = ?  |  d = 4.05
G = 6.67·10−11 N·m²/kg²  ;  M = 2·1030 kg
×4.37·10⁴
4.50·10⁹ m
2.406 ימים
3.340 ·10⁹ m
8.33 ·10⁴ m/s
7.13 ·10⁴ m/s
6.00 ·10⁴ m/s
4.013 m/s²
3.287 ·10⁻¹⁸ s²/m³
1.800 ·10²⁹ kg
11.1
0.00 ימים
4.50 ·10⁹ m
6.335 ימים
5.17 ·10⁴ m/s
0.593 m/s²
3.287 ·10⁻¹⁸ s²/m³
1.800 ·10²⁹ kg
14.82 ·10¹² J
1.334 ·10¹² J

G·M·m = m · 4π²·r = 4π²G·M
Tb = 1.51 · 86400 = 130464 s  ;  Td = 4.05 · 86400 = 349920 s k = Tb²rb³ = 1.7021·10¹⁰5.1777·10²⁷ = 3.2873·10⁻¹⁸ s²/m³
Tc²Tb² = rc³rb³ Tc = Tb · 1.3144·10²⁸5.1777·10²⁷ = 1.51 · 2.53861 = 1.51 · 1.59330 Tc = 2.406 ·86400 s = 2.0787·10⁵ s
rd³ = rb³ · Td²Tb² = 5.1777·10²⁷ · 1.2244·10¹¹1.7021·10¹⁰ = 5.1777·10²⁷ · 7.19366 rd³ = 3.7247·10²⁸  ;  rd = 3.7247·10²⁸ = 3.3396·10⁹ m
Tc² = k · rc³ = 3.2873·10⁻¹⁸ · 1.3144·10²⁸ = 4.3210·10¹⁰ Tc = 2.0787·10⁵ s = 2.406 ·86400 s rd³ = Td²k = 1.2244·10¹¹3.2873·10⁻¹⁸ = 3.7247·10²⁸

G·M·m = m·v²r  ;  v = G·Mr
v = 2π·rT  ;  T ∝ r1.5  ;  v ∝ rr1.5 = r−0.5
vb = 2π · 1.73·10⁹130464 = 8.33·10⁴ m/s vc = 2π · 2.36·10⁹2.0787·10⁵ = 7.13·10⁴ m/s vd = 2π · 3.3396·10⁹349920 = 6.00·10⁴ m/s
vb = 6.67·10⁻¹¹ · 1.80·10²⁹1.73·10⁹ = 6.942·10⁹ = 8.33·10⁴ m/s

gb = r  ;  v = 2π·rT
gb = 4π²·r²T²·r = 4π²·r
gb = 4π² · 1.73·10⁹(130464)² = 6.8298·10¹⁰1.7021·10¹⁰ = 4.013 m/s²
gb = G·Mrb² = 6.67·10⁻¹¹ · 1.8005·10²⁹2.9929·10¹⁸ = 4.013 m/s²
gb = vb²rb = 6.9418·10⁹1.73·10⁹ = 4.013 m/s²

W = G·Mb·mRb²

G·M·mbrb² = mb · 4π²·rbTb²  ;  M = 4π²·rb³G·Tb²
M = 39.4784 · 5.1777·10²⁷6.67·10⁻¹¹ · 1.7021·10¹⁰ = 2.04408·10²⁹1.135291 = 1.8005·10²⁹ kg
M = gb · rb²G = 4.0126 · 2.9929·10¹⁸6.67·10⁻¹¹ = 1.8005·10²⁹ kg
M = 39.4784 · 3.7247·10²⁸6.67·10⁻¹¹ · 1.2244·10¹¹ = 1.47052·10³⁰8.16702 = 1.8005·10²⁹ kg
1.80·10²⁹2·10³⁰ = 0.090

Ek = G·M·ms2R  ;  Ep = −G·M·msR E = Ek + Ep = −G·M·ms2R
ΔE = 0 − E = G·M·ms2R
ΔEIΔEII = MM = 2·10³⁰1.8005·10²⁹ = 11.1
vesc = 2·G·MR  ;  ΔE = ms·vesc²2ms·v²2 = G·M·ms2R
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