פתרון בגרות · מכניקה

✦ בנוי על ידי פהד גאנם ✦

vA(0) = 12 m/s  |  vA(10 s) = 8 m/s  |  vB(0) = 0  |  vB(10 s) = 8 m/s
aA = 8 − 1210 − 0 = −0.4 m/s²   ;   aB = 8 − 010 − 0 = +0.8 m/s²
xA(10 s) = 100 m  ;  xB(10 s) = 40 m  ;  xstation = 180 m  ;  aB,2 = −835 m/s²
0.00 s
×1
2.5 s
0.00 s
12.00 m/s
0.00 m/s
0.0 m
0.0 m
0.0 m
1
180.0 m

vA(0) = 12 m/s  ;  vA(10 s) = 8 m/s vB(0) = 0  ;  vB(10 s) = 8 m/s
a = ΔvΔt = v(10 s) − v(0)10 − 0 aA = 8 − 1210 − 0 = −410 = −0.4 m/s²
aB = 8 − 010 − 0 = 810 = +0.8 m/s²
vA(t) = 12 − 0.4·t  →  vA(10 s) = 12 − 4 = 8 m/s vB(t) = 0.8·t  →  vB(10 s) = 8 m/s

vA(10 s) = +8 m/s  ;  vB(10 s) = +8 m/s
xA = v0 + v2·t = 12 + 82·10 = 10 · 10 = 100 m xB = 0 + 82·10 = 4 · 10 = 40 m
xA(t) = 12t − 12(0.4)t² = 12t − 0.2t²  →  xA(10 s) = 120 − 20 = 100 m xB(t) = 12(0.8)t² = 0.4t²  →  xB(10 s) = 40 m xAxB = 10040 = 2.5

v² = v10² + 2a·Δx  →  0 = 8² + 2(−0.4)·Δx Δx = 2 · 0.4 = 640.8 = 80 m xstation = xA(10 s) + Δx = 100 + 80 = 180 m
0 = 12² + 2(−0.4)·x  →  x = 1440.8 = 180 m
v = v10 + a·Δt  →  0 = 8 + (−0.4)·Δt Δt = 80.4 = 20 s ttotal = 10 + 20 = 30 s
v̄ = v0 + v2 = 12 + 02 = 6 m/s t = x = 1806 = 30 s xA(30 s) = 12 · 30 − 0.2 · 30² = 360 − 180 = 180 m vA(30 s) = 12 − 0.4 · 30 = 0

d = xstation − xB(10 s) = 180 − 40 = 140 m
d = v10 + 02·ΔtB  →  140 = 8 + 02·ΔtB = 4·ΔtB ΔtB = 1404 = 35 s
tB,stop = 10 + 35 = 45 s  ;  tA,stop = 30 s Δt = tB,stop − tA,stop = 45 − 30 = 15 s
aB,2 = 0 − v10²2d = −8²2 · 140 = −64280 = −835 ≈ −0.229 m/s² ΔtB = 0 − 8−835 = 8 · 358 = 35 s d = 8 · 35 − 12 · 835 · 35² = 280 − 140 = 140 m

Δx = v̄ · Δtdrop  ;  Δtdrop = const
t (s) : 0   2.5   5   7.5   10   12.5   15   17.5   20 x (m) : 0   2.5   10   22.5   40   59.29   77.14   93.57   108.57 Δx (m) : 2.5   7.5   12.5   17.5   19.29   17.86   16.43   15.00

F (N)   |   3.5  |  4.0  |  4.5  |  5.0  |  5.5
a (m/s²)  |  1.9  |  2.7  |  3.4  |  4.2  |  5.0
T = F  ;  N = m·g  ;  f = μ·N = μ·m·g  ;  g = 10 m/s²
3.50 N
3.50 N
6.50 N
2.275 N
1.225 N
1.88 m/s²
0.00 m/s
0.00 m
1.94 m/s

T = F
N = m·g

ΣFy = N − m·g = 0 N = m·g
f = μ·N = μ·m·g
ΣFx = T − f = m·a F − μ·m·g = m·a a = F − μ·m·gm = Fm − μ·g

(3.5 , 1.9)   (4.0 , 2.7)   (4.5 , 3.4)   (5.0 , 4.2)   (5.5 , 5.0)
slope = a2 − a1F2 − F1 = 5.0 − 1.95.5 − 3.5 = 3.12.0 = 1.55 b = 1.9 − 1.55 · 3.5 = −3.525 m/s² a = 1.55 · F − 3.53
F0 = 3.5251.55 = 2.27 N

slope = ΔaΔF = 1m = 1.55 m = 1slope = 11.55 = 0.645 ≈ 0.65 kg
1.9 = 1.55 · 3.5 + b  ;  b = 1.9 − 5.425 = −3.525 −μ·g = −3.525  ;  μ = 3.52510 = 0.3525 ≈ 0.35
F0 = 3.5251.55 = 2.274 N μ = F0m·g = 2.2740.645 · 10 = 0.3525 ≈ 0.35
F̄ = 4.5 N  ;  ā = 17.25 = 3.44 m/s² slope = Σ(F − F̄)(a − ā)Σ(F − F̄)² = 3.852.5 = 1.54 m = 11.54 = 0.649 kg  ;  b = 3.44 − 1.54 · 4.5 = −3.49  ;  μ = 0.349
a = F0.65 − 3.5 1.88  |  2.65  |  3.42  |  4.19  |  4.96 m/s² (מחושב) 1.9   |  2.7   |  3.4   |  4.2   |  5.0 m/s² (נמדד)
WT = F · d = 5.0 · 1 = 5.0 J Wf = −μ·m·g·d = −0.35 · 0.65 · 10 · 1 = −2.275 J W = 5.0 − 2.275 = 2.725 J v = 2 · 2.7250.65 = 8.385 = 2.90 m/s v = 2·a·d = 2 · 4.19 · 1 = 2.90 m/s

fmax = μ·N = μ·m·g = 0.35 · 0.65 · 10 = 2.275 N
F = 1.5 N  ;  fmax = 2.275 N  ;  fmax − F = 0.775 N f = T = F = 1.5 N  ;  ΣF = 0  ;  a = 0
a = 1.55 · 1.5 − 3.525 = −1.2 m/s²
ΣF = F − μ·m·g = 1.5 − 2.275 = −0.775 N

m = 2 kg  |  a = 3 m  |  ℓ = 1 m  |  α = 30°  |  g = 10 m/s²  |  Tmax = 45 N
sin 30° = 0.5  ;  cos 30° = 0.866  ;  tan 30° = 0.577  ;  m·g = 20 N
r = a + ℓ·sin α = 3 + 1 · 0.5 = 3.5 m   ;   T = m·gcos α   ;   T·sin α = m·ω²·r
0.204 Hz
2.0 kg
3.0 m
1.0 m
45 N
30.00°
3.50 m
1.28 rad/s
4.89 s
4.50 m/s
23.09 N
11.55 N
20.00 N
20.00 N
1.15

r = a + ℓ·sin α = 3 + 1 · 0.5 = 3.5 m m·g = 2 · 10 = 20 N
Fc = T·sin α   ;   ΣFx = m·ω²·r
ΣFy = m·ay = 0   ;   T·cos α = m·g
Tm·g = 1cos 30° = 23 = 1.155

ay = 0   ;   ax = ac = ω²·r
ΣFy = m·ay = 0 T·cos α − m·g = 0 T = m·gcos α = 2 · 10cos 30° = 403 = 23.09 N
Fc = m·g·tan α = 20 · 0.5774 = 11.547 N T = (m·g)² + Fc² = 400 + 133.33 = 533.33 = 23.09 N

α = 0   ;   T0 = m·g = 2 · 10 = 20 N
T = m·gcos α = m·g0.866 = 1.1547 · m·g = 1.1547 · T0 TT0 = 1cos 30° = 1.1547
20 N   ;   23.09 N   ;   ΔT = 3.09 N

r = a + ℓ·sin α = 3 + 1 · sin 30° = 3 + 0.5 = 3.5 m
ΣFx = m·ac   ;   T·sin α = m·ω²·r 23.094 · 0.5 = 2 · ω² · 3.5 11.547 = 7 · ω² ω² = 11.5477 = 1.6496 s⁻²   ;   ω = 1.2844 rad/s
f = ω = 1.28446.2832 = 0.204 Hz Tמחזור = 1f = 4.89 s
tan α = ω²·rg   ;   ω = g·tan αr = 10 · 0.57743.5 = 1.2844 rad/s
v = ω·r = 1.2844 · 3.5 = 4.4952 m/s Tמחזור = 2π·rv = 21.9914.4952 = 4.892 s   ;   f = 0.2044 Hz Fc = m·v²r = 2 · 20.2073.5 = 11.547 N = T·sin α

Tmax·cos αmax = m·g cos αmax = m·gTmax = 2045 = 49 = 0.4444   ;   αmax = 63.61° sin αmax = 659 = 0.8958   ;   tan αmax = 654 = 2.0156
rmax = a + ℓ·sin αmax = 3 + 1 · 0.8958 = 3.8958 m
Tmax·sin αmax = m·ωmax²·rmax 45 · 0.8958 = 2 · ωmax² · 3.8958   ;   40.311 = 7.7916 · ωmax² ωmax² = 40.3117.7916 = 5.1737 s⁻²   ;   ωmax = 2.2746 rad/s fmax = ωmax = 2.27466.2832 = 0.362 Hz
ωmax = g·tan αmaxrmax = 10 · 2.01563.8958 = 2.2746 rad/s vmax = ωmax·rmax = 8.8613 m/s   ;   Tמחזור = 2π·rmaxvmax = 2.762 s Fc = m·vmax²rmax = 40.311 N = Tmax·sin αmax

mA = 0.14 kg  |  mB = ?  |  vA = +3 m/s  |  v′A = +1 m/s  |  vB = −1.5 m/s  |  v′B = +5.5 m/s
Δt = 10 ms − 5 ms = 5 ms = 5·10⁻³ s = 0.005 s  ;  ΔvA = −2 m/s  ;  ΔvB = +7 m/s
1 : 500
0.040 kg
+3.0 m/s
−1.5 m/s
5 ms
0.00 ms
+3.00 m/s
−1.50 m/s
+0.420 kg·m/s
−0.060 kg·m/s
0.360 kg·m/s
2.000 m/s
0.675 J
0.000 N·s
0.000 N·s
0.0 N
0.0 N

vA > 0  ;  vB < 0
vA = +3 m/s  ;  vB = −1.5 m/s
|Δv1| = 2 m/s  ;  |Δv2| = 7 m/s

mA·vA + mB·vB = mA·v′A + mB·v′B 0.14 · 3 + mB · (−1.5) = 0.14 · 1 + mB · 5.5 0.42 − 0.14 = 5.5·mB + 1.5·mB 0.28 = 7·mB mB = 0.287 = 0.04 kg
mA·|ΔvA| = mB·|ΔvB| 0.14 · 2 = mB · 7 mB = 0.287 = 0.04 kg
Ek = ½·0.14·3² + ½·0.04·1.5² = 0.63 + 0.045 = 0.675 J E′k = ½·0.14·1² + ½·0.04·5.5² = 0.07 + 0.605 = 0.675 J
vA − vB = 3 − (−1.5) = 4.5 m/s v′B − v′A = 5.5 − 1 = 4.5 m/s vcm = 0.14·3 + 0.04·(−1.5)0.18 = 0.360.18 = 2 m/s v′cm = 0.14·1 + 0.04·5.50.18 = 0.360.18 = 2 m/s

J = ΔpA = mA·v′A − mA·vA = mA·(v′A − vA) J = 0.14 · (1 − 3) = 0.14 · (−2) = −0.28 N·s
JB = mB·(v′B − vB) = 0.04 · (5.5 − (−1.5)) = 0.04 · 7 = +0.28 N·s ΔpA + ΔpB = (−0.28) + (+0.28) = 0

Δt = 10 − 5 = 5 ms = 5·10⁻³ s = 0.005 s
F = JΔt = ΔpAΔt F = −0.285·10⁻³ = −56 N
aA = 1 − 3(10 − 5)·10⁻³ = −25·10⁻³ = −400 m/s² F = mA·aA = 0.14 · (−400) = −56 N
aB = 5.5 − (−1.5)5·10⁻³ = 75·10⁻³ = +1400 m/s² FB = mB·aB = 0.04 · 1400 = +56 N

FAB = − FBA
JAB = FAB·Δt = − FBA·Δt = − JBA
|JA| = 0.14 · |1 − 3| = 0.28 N·s |JB| = 0.04 · |5.5 − (−1.5)| = 0.28 N·s
Δv = Jm  ;  |ΔvA| = 0.280.14 = 2 m/s  ;  |ΔvB| = 0.280.04 = 7 m/s

m = 2 kg  |  μ = 0.2  |  g = 10 m/s²  |  x0 = 0  |  xA = 5 m
N = m·g = 2 · 10 = 20 N  ;  f = μ·N = 0.2 · 20 = 4 N
F = 5 N  (0 ≤ x ≤ 3 m)  ;   F = 5 + 5·(x − 3) N  (3 m ≤ x ≤ 5 m)
k = 15 − 55 − 3 = 102 = 5 N/m
0.20
2.0 kg
30°
0.00 m
0.00 m/s
0.00 m²/s²
0.00 J
5.00 N
4.00 N
20.00 N
0.00 J
0.00 J
8.75 m
17.11 N
3.42 N
19.04 J
9.76 m

ΔW = F·Δx  ;  WF = Σ F·Δx = S
S1 = F·Δx = 5 · 3 = 15 J S2 = (5 + 15) · 22 = 402 = 20 J WF = S1 + S2 = 15 + 20 = 35 J
k = 15 − 55 − 3 = 102 = 5 N/m F(x) = 5 + 5·(x − 3) N  (3 ≤ x ≤ 5) WF = ∫₀³ 5 dx + ∫₃⁵ [5 + 5(x − 3)] dx = 15 + (10 + 10) = 35 J

ΣFy = 0  ;  N = m·g = 2 · 10 = 20 N f = μ·N = 0.2 · 20 = 4 N
Wf = f·d·cos 180° = −f·xA = −μ·m·g·xA Wf = −0.2 · 2 · 10 · 5 = −4 · 5 = −20 J
|Wf| = 4 · 5 = 20 J  ;  Wf = −20 J

Wtotal = WF + Wf = 35 + (−20) = 15 J
Wtotal = ΔEk = 12·m·vA² − 0 15 = 12 · 2 · vA² vA² = 2 · 152 = 15 m²/s² vA = 15 = 3.87 m/s
a1 = F − fm = 5 − 42 = 0.5 m/s² v3² = 2·a1·Δx = 2 · 0.5 · 3 = 3 m²/s²  →  v3 = 1.73 m/s 3 → 5 m :   W = 20 − 4 · 2 = 12 J 12·2·vA² = 3 + 12 = 15  →  vA² = 15  →  vA = 3.87 m/s

−f·d = 0 − 12·m·vA² d = m·vA²2·f = m·vA²2·μ·m·g = vA²2·μ·g d = 152 · 0.2 · 10 = 154 = 3.75 m
xB = xA + d = 5 + 3.75 = 8.75 m
a = −fm = −42 = −2 m/s² 0 = vA² + 2·a·d = 15 − 4·d  →  d = 154 = 3.75 m t = vA|a| = 3.8732 = 1.94 s  ;  d = vA·t2 = 3.75 m

W(F1) = ∫ F1·cos α dx = ∫ F dx = 35 J
N1 = m·g − F1·sin α  <  m·g f1 = μ·N1 = μ·(m·g − F1·sin α)  <  μ·m·g = 4 N
Ek(A) = 35 − μ·(m·g − F1·sin α)·5  >  35 − 20 = 15 J
d = Ek(A)f  ;  Ek,C(A) > Ek,B(A)  →  dC > dB = 3.75 m xC = 5 + dC  >  5 + 3.75 = xB = 8.75 m

G = 6.67·10−11 N·m²/kg²  |  M = 86.98·1024 kg = 8.698·1025 kg  |  R = 26.1·106 m = 2.61·107 m
rM = 13·107 m = 1.3·108 m  ;  rA = 19·107 m = 1.9·108 m  ;  ME = 5.974·1024 kg  ;  RE = 6.38·106 m
G·M = 6.67·10−11 · 8.698·1025 = 5.801566·1015 m³/s²   ;   R² = 6.8121·1014
1.30·10⁸ m
1.90·10⁸ m
8.698·10²⁵ kg
2.61·10⁷ m
8.52 m/s²
0.343 m/s²
0.161 m/s²
1.223·10⁵ s
33.96 h
2.160·10⁵ s
60.01 h
6.68·10³ m/s
5.53·10³ m/s
4.616·10⁵ s
8.156·10⁵ s
1.767
1.767
1.767
0.00
0.00

G·M·m = m·g g = G·M
M = 86.98·1024 = 8.698·1025 kg  ;  R = 26.1·106 = 2.61·107 m g = 6.67·10−11 · 8.698·1025(2.61·107 = 5.801566·10156.8121·1014 = 8.5166 m/s² g ≈ 8.5 m/s²
gUgE = MME · (RER)² = 86.985.974 · (6.3826.1)² = 14.5598 · 0.059753 = 0.86999 gE = 6.67·10−11 · 5.974·1024(6.38·106 = 3.984658·10144.07044·1013 = 9.7893 m/s² gU = 0.86999 · 9.7893 = 8.5166 m/s²

G·M·mMrM² = mM·ar ar = G·MrM²
rM = 13·107 = 1.3·108 m  ;  rM² = 1.69·1016 ar = 5.801566·10151.69·1016 = 0.34329 m/s² ≈ 0.34 m/s²
ar = g · (RrM)² = 8.5166 · (2.61·1071.3·108)² = 8.5166 · (0.200769)² ar = 8.5166 · 0.0403083 = 0.34329 m/s²

ar = ω²·rM = 4π²·rMTM² TM = 2πrMar
TM = 2π1.3·1080.34329 = 2π3.786908·108 = 2π · 19459.98 TM = 1.22271·105 s ≈ 1.22·105 s
ar = rM  →  v = ar·rM = 0.34329 · 1.3·108 = 4.46274·107 = 6680.4 m/s TM = 2π·rMv = 8.168141·1086680.4 = 1.22271·105 s
TM = 2πrM³G·M = 2π2.197·10245.801566·1015 = 2π3.786908·108 TM = 1.22271·105 s

G·M·m = m · 4π²·r T² = 4π²·r³G·M  →  T = 2πG·M
TA²TM² = rA³rM³  →  TATM = (rArM)1.5 TATM = (19·10713·107)1.5 = (1.461538)1.5 = 68592197 = 3.121985 = 1.7669 TATM ≈ 1.77
TA = 2π(1.9·1085.801566·1015 = 2π1.1822669·109 = 2π · 34384.11 TA = 2.16042·105 s TATM = 2.16042·1051.22271·105 = 1.7669

T = 2πG·ME TבTא = rב³rא³ = (rבrא)1.5
rבrא = rArM = 1913  →  TבTא = (1913)1.5 = 1.7669
G·ME = g·RE² = 10 · (6.38·106)² = 4.07044·1014 m³/s² Tא = 2π2.197·10244.07044·1014 = 2π · 73467.3 = 4.6161·105 s Tב = 2π6.859·10244.07044·1014 = 2π · 129810.5 = 8.1562·105 s TבTא = 8.1562·1054.6161·105 = 1.7669
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