α : ΔA = −4 , ΔZ = −2 (⁴₂He)
β⁻ : ΔA = 0 , ΔZ = +1 (⁰₋₁e)
ΔA = 226 − 214 = 12
Nα = ΔA4 = 124 = 3
Z (3α) = 88 − 2·3 = 82
Nβ = 84 − 82 = 2
²²⁶₈₈Ra ⟶ ²¹⁴₈₄Po + 3·⁴₂He + 2·⁰₋₁e
A : 226 = 214 + 12 ✓
Z : 88 = 84 + 6 − 2 ✓
²²⁶₈₈Ra ⟶(α) ²²²₈₆Rn ⟶(α) ²¹⁸₈₄Po ⟶(α) ²¹⁴₈₂Pb ⟶(β⁻) ²¹⁴₈₃Bi ⟶(β⁻) ²¹⁴₈₄Po