השראה אלקטרומגנטית
✦ בנוי על ידי פהד גאנם ✦
العربية
☀ מצב בהיר
5.1
▾
✕
Φ = B·A·cosθ | ε = −N·
ΔΦ
Δt
| ε = B·L·v
0.40 T
0.010 m²
200
0.40 T/s
0
0
0
0
0
0
Φ₀ = B·A·cos0° = 0.40 · 0.010 · 1 = 4.0·10⁻³ Wb
ΔΦ = Φ₁ − Φ₀ = 0 − 4.0·10⁻³ = −4.0·10⁻³ Wb
ΔΦ
Δt
=
−4.0·10⁻³ Wb
0.10 s
= −0.040 Wb/s
ε = −N·
ΔΦ
Δt
= −200 ·
−4.0·10⁻³ Wb
0.10 s
= 8.0 V
5.1
▾
✕
ε = −N ·
ΔΦ
Δt
| I =
ε
R
| P =
ε²
R
| W = E
2.0 m/s
3.0
150
0
0
0
0
0
0
0
0
0
0
ε = −N ·
ΔΦ
Δt
= −150 ·
0.012
0.040
= −150 · 0.30 = −45 V
5.2
▾
✕
ε = N·B·A·ω·sin(ωt) | ε
max
= N·B·A·ω | V
eff
=
V
max
√
2
|
V₂
V₁
=
N₂
N₁
| V₁·I₁ = V₂·I₂
0.50 T
0.020 m²
100
50 Hz
325 V
50 Ω
1000
50
240 V
2.0 A
0
0
0
0
0
0
0
0
0
0
0
0
0
V
eff
=
V
max
√
2
⇒ V
max
= V
eff
·
√
2
V
max
= 230 ·
√
2
= 230 · 1.414 = 325.2 V
V₂
V₁
=
N₂
N₁
⇒ V₂ = V₁ ·
N₂
N₁
= 240 ·
50
1000
= 12 V
P = V₂ · I₂ = 12 · 2.0 = 24 W
I₁ =
P
V₁
=
24
240
= 0.10 A
5.4
▾
✕
c =
1
√
ε₀·μ₀
| λ =
c
f
501 THz
80%
0
0
0
∮ E·dA =
Q
ε₀
∮ B·dA = 0
∮ E·dl = −
ΔΦ
B
Δt
∮ B·dl = μ₀·I + μ₀·ε₀·
ΔΦ
E
Δt
μ₀ = 4π ·10⁻⁷ = 1.2566 ·10⁻⁶
ε₀·μ₀ = 8.854 ·10⁻¹² · 1.2566 ·10⁻⁶ = 1.1126 ·10⁻¹⁷
c =
1
√
ε₀·μ₀
=
√
1
ε₀·μ₀
=
√
1
1.1126 ·10⁻¹⁷
c =
√
8.988 ·10¹⁶
= 2.998 ·10⁸ m/s
→
🏠
♿