המודל הדואלי של הקרינה
✦ בנוי על ידי פהד גאנם ✦
العربية
☀ מצב בהיר
4.1
▾
✕
E = h·f =
h·c
λ
| E
k,max
= h·f − W | V
stop
=
E
k,max
e
| f
0
=
W
h
| λ
0
=
h·c
W
400 nm
60 %
0.0 V
0
0
0
0
0
0
0
0
E =
h·c
λ
=
1240 eV·nm
400 nm
= 3.10 eV
E
k,max
= E − W = 3.10 − 2.30 = 0.80 eV
V
stop
=
E
k,max
e
=
0.80 eV
e
= 0.80 V
λ
0
=
h·c
W
=
1240 eV·nm
2.30 eV
= 539 nm
4.2
▾
✕
Δλ = λ
C
·(1 − cos θ) | λ
C
=
h
m
e
·c
= 2.426·10⁻¹² m | p =
h
λ
0.0200 nm
90°
0
0
0
0
0
0
0
0
λ
C
=
h
m
e
·c
=
6.626·10⁻³⁴
9.109·10⁻³¹ · 2.998·10⁸
= 2.426·10⁻¹² m
Δλ = λ
C
·(1 − cos 90°) = 2.426·10⁻¹² · (1 − 0) = 2.426·10⁻¹² m
λ′ = λ + Δλ = 0.020000 + 0.002426 = 0.022426 nm
E =
h·c
λ
=
1240
0.020000
= 62000 eV
E′ =
h·c
λ′
=
1240
0.022426
= 55293 eV
ΔE = E − E′ = 62000 − 55293 = 6707 eV
4.3
▾
✕
E
max
= e·V | λ
min
=
h·c
e·V
=
1240 eV·nm
E
max
50 kV
5.0 mA
50
0
0
0
0
0
0
0
E = e·V = e · 50000 V = 50000 eV = 5.0 · 10⁴ eV
λ
min
=
h·c
E
=
1240 eV·nm
50000 eV
= 0.0248 nm
0.0248 nm · 1000 = 24.8 pm
4.4
▾
✕
E = h·f =
h·c
λ
| p =
h
λ
=
E
c
550 nm
0 / 3
0 / 3
0 / 1
0
550
2.25
1.20
E = h·f =
h·c
λ
=
1240 eV·nm
550 nm
= 2.25 eV
p =
h
λ
=
6.626·10⁻³⁴
550·10⁻⁹
= 1.20·10⁻²⁷ kg·m/s
→
🏠
♿